>[!summary]
Assuming vectors are some form ${\begin{bmatrix} x_1 \\ x_2\end{bmatrix}}$ in a $\mathbb{R^2}$ plane create a point. If we multiply this vector by some scalar, you get a line. We can move this vector in any way to create a new parallel line.
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Directed line segments are a way of defining vectors in any reference (changing our reference away from the origin), and are used to define and determine others vectors are equal.
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**Key equations:**
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Vector equations for parallel lines:
$x = \vec{p} + t\vec{d}$
>[!info]+ Read Time
**⏱ 3 mins**
# Defining Vector Equations for Lines in 2D
>[!warning] Assumptions
For making lines in $\mathbb{R^2}$ we will vector addition and multiplication are valid from [[Vectors, Vectors Addiction & Vector Multiplication]].
If we have a vector $\vec{d}$ in $\mathbb{R^2}$ this is some vector. If multiple this vector by a scalar multiple we can make a line with some direction, which is seen from the figure below.
If we have another vector $\vec{p} \in \mathbb{R^2}$ we can make another vector by adding vector d and p. This gives us $\vec{p} + \vec{d}$. If we do the same as before by multiplying $\vec{d}$ by a scalar, we get a new parallel line, seen below, so the key equation here is $x = \vec{p} + t\vec{d}$
![[vq_1.png]]
>[!note] Explanation
If we have some vectors in $\mathbb{R^2}$ and some vector $\vec{d}$ we can do some things to manipulate this vector.
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Multiplying this vector creates a line, and we can move the vector and do the same to create a parallel line to the original vector $\vec{d}$
## Directed Line Segments
Sometimes is important to denote a line segment with direction. This is useful for making geometry statements in reference to some point such as O like in the example below.
>[!warning] Assumption
In our definition directed line segments for $\mathbb{R^2}$ we assume it in reference with point O on the graph below. But our reference point can be anywhere.
We will denote the directed line segments from P to Q by $\vec{PQ}$
Like an arrow going from point P to point Q.
As well our vector $\vec{OP}$ as $\vec{p}$ and $\vec{OQ}$ as $\vec{q}$.
![[LR2_2.png|500]]
As well vectors can be equal if they give the same result. Like in the example below, where T-R = O-Q
![[VEQ_1.png|500]]
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