quot; (where $x$ is a real number) is true, but its converse "If $x^2 > 0$ then $x > 0quot; is not true because of the [[counterexample]] $x = -1$. If it happens that both $P \rightarrow Q$ and $Q \rightarrow P$, then we say "$P$ [[if and only if]] $Qquot;. ## Examples Here are some conditional statements and their converses: | Statement | Converse | | -------------------------------- | -------------------------------- | | If it's snowing, then it's cold. | If it's cold, then it's snowing. | | If $x > 4$ then $x^2 > 16$. | If $x^2 > 16$ then $x > 4$. | | My coffee being hot is a consequence of it being freshly brewed. | My coffee being freshly brewed is a consequence of it being hot. | | | ## Resources <iframe src="https://player.vimeo.com/video/588861844?h=3596e8dbfd" width="640" height="360" frameborder="0" allow="autoplay; fullscreen; picture-in-picture" allowfullscreen></iframe> <p><a href="https://vimeo.com/588861844">Screencast 2.4: Converse, contrapositive, and inverse</a> from <a href="https://vimeo.com/user132700952">Robert Talbert</a> on <a href="https://vimeo.com">Vimeo</a>.</p> Other resources: - Tutorial: [Logical converse](https://www.mathsisfun.com/definitions/converse-logic-.html) - Tutoral: [Converse and contrapositive](https://www.cs.odu.edu/~toida/nerzic/content/logic/prop_logic/converse/converse_intro.html)